JEE MainPhysicsAtoms and NucleiNumerical+4 / −1
The K X-ray of molybdenum has wavelength 0.071 nm. If the energy of a molybdenum atoms with a K electron knocked out is 27.5 keV, the energy of this atom when an L electron is knocked out will be keV. (Round off to the nearest integer) [h = 4.14 10 15 eVs, c = 3 108 ms 1]
Numerical answer
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