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Alternating Current question

2022 · 24 Jun · Shift 1 · Q64
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Alternating Current question

2022 · 24 Jun · Shift 1 · Q64

JEE MainPhysicsAlternating CurrentNumerical+4 / −1
As shown in the figure an inductor of inductance 200 mH is connected to an AC source of emf 220 V and frequency 50 Hz. The instantaneous voltage of the source is 0 V when the peak value of current is aπ{{\sqrt a } \over \pi }πa​​ A. The value of aaa is ‾\underline{\hspace{2cm}}​. JEE Main 2022 (Online) 24th June Morning Shift Physics - Alternating Current Question 79 English
Numerical answer
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