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Alternating Current question

2021 · 27 Aug · Shift 1 · Q60
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Alternating Current question

2021 · 27 Aug · Shift 1 · Q60

JEE MainPhysicsAlternating CurrentNumerical+4 / −1
The alternating current is given by i={42sin⁡(2πTt)+10}Ai = \left\{ {\sqrt {42} \sin \left( {{{2\pi } \over T}t} \right) + 10} \right\}Ai={42​sin(T2π​t)+10}A The r.m.s. value of of this current is ................. A.
Numerical answer
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