JEE MainPhysicsAlternating CurrentMCQ+4 / −1
A 750 Hz, 20 V (rms) source is connected to a resistance of 100 , an inductance of 0.1803 H and a capacitance of 10 F all in series. The time in which the resistance (heat capacity 2 J/oC) will get heated by 10oC. (assume no loss of heat to the surroudnings) is close to :
- A348 s
- B418 s
- C245 s
- D365 s
View written solutionFree
Correct answer: A
- Given data
- Frequency:
- RMS voltage:
- Resistance:
- Inductance:
- Capacitance:
- Heat capacity of resistance:
- Required temperature rise:
So, heat required is
- Find angular frequency
Numerically,
- Calculate reactances
Inductive reactance:
Capacitive reactance:
Net reactance:
- Find impedance of series RLC circuit
- Find current in the circuit
- Power dissipated in the resistor
Only the resistor dissipates real power:
- Find time required to produce 20 J heat
Since we get
Thus the required time is close to
- Option check
- A: ✅
- B: ❌
- C: ❌
- D: ❌
Therefore, the correct option is A.
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