JEE MainPhysicsAlternating CurrentNumerical+4 / −1
In a series LR circuit, power of 400W is dissipated from a source of 250 V, 50 Hz. The power factor of the circuit is 0.8. In order to bring the power factor to unity, a capacitor of value C is added in series to the L and R. Taking the value of C as F, then value of n is .
Numerical answer
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