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Alternating Current question

2007 · Shift 0 · Q71

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JEE Main
Physics
Alternating Current
2007 · Shift 0 · Q71

Alternating Current question

2007 · Shift 0 · Q71

JEE MainPhysicsAlternating CurrentMCQ+4 / −1

In an

a.c.

circuit the voltage applied is

E = {E_0}\,\sin \,\omega t.

The resulting current in the circuit is

I = {I_0}\sin \left( {\omega t - {\pi \over 2}} \right).

The power consumption in the circuit is given by

A
$P = \sqrt 2 {E_0}{I_0}$
B
$P = {{{E_0}{I_0}} \over {\sqrt 2 }}$
C
$P=zero$
D
$P = {{{E_0}{I_0}} \over 2}$

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