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Vector Algebra question

2023 · 13 Apr · Shift 2 · Q34
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  5. /2023 · 13 Apr · Shift 2 · Q34

Vector Algebra question

2023 · 13 Apr · Shift 2 · Q34

JEE MainMathematicsVector AlgebraMCQ+4 / −1
Let for a triangle ABC\mathrm{ABC}ABC, AB→=−2i^+j^+3k^CB→=αi^+βj^+γk^CA→=4i^+3j^+δk^\overrightarrow{\mathrm{AB}}=-2 \hat{i}+\hat{j}+3 \hat{k}\overrightarrow{\mathrm{CB}}=\alpha \hat{i}+\beta \hat{j}+\gamma \hat{k}\overrightarrow{\mathrm{CA}}=4 \hat{i}+3 \hat{j}+\delta \hat{k}AB=−2i^+j^​+3k^CB=αi^+βj^​+γk^CA=4i^+3j^​+δk^ If δ>0\delta \gt 0δ>0 and the area of the triangle ABC\mathrm{ABC}ABC is 565 \sqrt{6}56​, then CB→⋅CA→\overrightarrow{C B} \cdot \overrightarrow{C A}CB⋅CA is equal to
  1. A
    60
  2. B
    54
  3. C
    120
  4. D
    108
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