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Vector Algebra question

2021 · 18 Mar · Shift 2 · Q27
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  5. /2021 · 18 Mar · Shift 2 · Q27

Vector Algebra question

2021 · 18 Mar · Shift 2 · Q27

JEE MainMathematicsVector AlgebraMCQ+4 / −1
Let a→\overrightarrow aa and b→\overrightarrow bb be two non-zero vectors perpendicular to each other and ∣a→∣=∣b→∣|\overrightarrow a | = |\overrightarrow b |∣a∣=∣b∣. If ∣a→×b→∣=∣a→∣|\overrightarrow a \times \overrightarrow b | = |\overrightarrow a |∣a×b∣=∣a∣, then the angle between the vectors (a→+b→+(a→×b→))\left( {\overrightarrow a + \overrightarrow b + \left( {\overrightarrow a \times \overrightarrow b } \right)} \right)(a+b+(a×b)) and a→{\overrightarrow a }a is equal to :
  1. A
    sin⁡−1(16){\sin ^{ - 1}}\left( {{1 \over {\sqrt 6 }}} \right)sin−1(6​1​)
  2. B
    cos⁡−1(12){\cos ^{ - 1}}\left( {{1 \over {\sqrt 2 }}} \right)cos−1(2​1​)
  3. C
    sin⁡−1(13){\sin ^{ - 1}}\left( {{1 \over {\sqrt 3 }}} \right)sin−1(3​1​)
  4. D
    cos⁡−1(13){\cos ^{ - 1}}\left( {{1 \over {\sqrt 3 }}} \right)cos−1(3​1​)
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