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Vector Algebra question

2020 · 7 Jan · Shift 2 · Q35
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  5. /2020 · 7 Jan · Shift 2 · Q35

Vector Algebra question

2020 · 7 Jan · Shift 2 · Q35

JEE MainMathematicsVector AlgebraMCQ+4 / −1
Let a→\overrightarrow aa, b→\overrightarrow bb and c→\overrightarrow cc be three unit vectors such that a→+b⃗+c→=0→\overrightarrow a + \vec b + \overrightarrow c = \overrightarrow 0a+b+c=0. If λ=a→.b⃗+b⃗.c→+c→.a→\lambda = \overrightarrow a .\vec b + \vec b.\overrightarrow c + \overrightarrow c .\overrightarrow aλ=a.b+b.c+c.a and d→=a→×b⃗+b⃗×c→+c→×a→\overrightarrow d = \overrightarrow a \times \vec b + \vec b \times \overrightarrow c + \overrightarrow c \times \overrightarrow ad=a×b+b×c+c×a, then the ordered pair, (λ,d→)\left( {\lambda ,\overrightarrow d } \right)(λ,d) is equal to :
  1. A
    (32,3a→×c→)\left( {{3 \over 2},3\overrightarrow a \times \overrightarrow c } \right)(23​,3a×c)
  2. B
    (−32,3c→×b→)\left( { - {3 \over 2},3\overrightarrow c \times \overrightarrow b } \right)(−23​,3c×b)
  3. C
    (−32,3a→×b→)\left( { - {3 \over 2},3\overrightarrow a \times \overrightarrow b } \right)(−23​,3a×b)
  4. D
    (32,3b→×c→)\left( {{3 \over 2},3\overrightarrow b \times \overrightarrow c } \right)(23​,3b×c)
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