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Vector Algebra question

2019 · 9 Apr · Shift 1 · Q28
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  5. /2019 · 9 Apr · Shift 1 · Q28

Vector Algebra question

2019 · 9 Apr · Shift 1 · Q28

JEE MainMathematicsVector AlgebraMCQ+4 / −1
Let α→=3i^+j^\overrightarrow \alpha = 3\widehat i + \widehat jα=3i+j​ and β→=2i^−j^+3k^\overrightarrow \beta = 2\widehat i - \widehat j + 3 \widehat kβ​=2i−j​+3k. If β→=β→1−β2→\overrightarrow \beta = {\overrightarrow \beta _1} - \overrightarrow {{\beta _2}}β​=β​1​−β2​​, where β→1{\overrightarrow \beta _1}β​1​ is parallel to α→\overrightarrow \alphaα and β2→\overrightarrow {{\beta _2}}β2​​ is perpendicular to α→\overrightarrow \alphaα, then β→1×β2→{\overrightarrow \beta _1} \times \overrightarrow {{\beta _2}}β​1​×β2​​ is equal to
  1. A
    3i^−9j^−5k^3\widehat i - 9\widehat j - 5\widehat k3i−9j​−5k
  2. B
    12{1 \over 2}21​(−3i^+9j^+5k^- 3\widehat i + 9\widehat j + 5\widehat k−3i+9j​+5k)
  3. C
    −3i^+9j^+5k^- 3\widehat i + 9\widehat j + 5\widehat k−3i+9j​+5k
  4. D
    12{1 \over 2}21​(3i^−9j^+5k^3\widehat i - 9\widehat j + 5\widehat k3i−9j​+5k)
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