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Vector Algebra question

2008 · Shift 0 · Q43
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Vector Algebra question

2008 · Shift 0 · Q43

JEE MainMathematicsVector AlgebraMCQ+4 / −1
The non-zero vectors are a→,b→{\overrightarrow a ,\overrightarrow b }a,b and c→{\overrightarrow c }c are related by a→=8b→{\overrightarrow a = 8\overrightarrow b }a=8b and c→=−7b→  .{\overrightarrow c = - 7\overrightarrow b \,\,.}c=−7b. Then the angle between a→{\overrightarrow a }a and c→{\overrightarrow c }c is :
  1. A
    000
  2. B
    π4{\pi \over 4}4π​
  3. C
    π2{\pi \over 2}2π​
  4. D
    π\piπ
View written solutionFree

Correct answer: D

  1. We are given: a⃗=8b⃗,c⃗=−7b⃗\vec a = 8\vec b, \qquad \vec c = -7\vec ba=8b,c=−7b where a⃗,b⃗,c⃗\vec a, \vec b, \vec ca,b,c are non-zero vectors.

  2. Since a⃗=8b⃗\vec a = 8\vec ba=8b, the vector a⃗\vec aa is in the same direction as b⃗\vec bb because the scalar 8>08>08>0.

  3. Since c⃗=−7b⃗\vec c = -7\vec bc=−7b, the vector c⃗\vec cc is in the opposite direction to b⃗\vec bb because the scalar −7<0-7<0−7<0.

  4. Therefore, a⃗\vec aa and c⃗\vec cc are in opposite directions.

  5. The angle between two opposite vectors is: π\piπ

  6. Hence, the correct option is: D: π\boxed{\text{D: } \pi}D: π​

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