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Statistics question

2023 · 1 Feb · Shift 2 · Q24
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  5. /2023 · 1 Feb · Shift 2 · Q24

Statistics question

2023 · 1 Feb · Shift 2 · Q24

JEE MainMathematicsStatisticsMCQ+4 / −1
Let 9=x1<x2<…<x79=x_{1} \lt x_{2} \lt \ldots \lt x_{7}9=x1​<x2​<…<x7​ be in an A.P. with common difference d. If the standard deviation of x1,x2...,x7x_{1}, x_{2}..., x_{7}x1​,x2​...,x7​ is 4 and the mean is xˉ\bar{x}xˉ, then xˉ+x6\bar{x}+x_{6}xˉ+x6​ is equal to :
  1. A
    2(9+87)2\left(9+\frac{8}{\sqrt{7}}\right)2(9+7​8​)
  2. B
    25
  3. C
    18(1+13)18\left(1+\frac{1}{\sqrt{3}}\right)18(1+3​1​)
  4. D
    34
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