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Sets and Relations question

2025 · 29 Jan · Shift 2 · Q26
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  5. /2025 · 29 Jan · Shift 2 · Q26

Sets and Relations question

2025 · 29 Jan · Shift 2 · Q26

JEE MainMathematicsSets and RelationsMCQ+4 / −1
Let S=N∪{0}\mathrm{S}=\mathbf{N} \cup\{0\}S=N∪{0}. Define a relation R from S to R\mathbf{R}R by : R={(x,y):log⁡ey=xlog⁡e(25),x∈ S,y∈R}.\mathrm{R}=\left\{(x, y): \log _{\mathrm{e}} y=x \log _{\mathrm{e}}\left(\frac{2}{5}\right), x \in \mathrm{~S}, y \in \mathbf{R}\right\} .R={(x,y):loge​y=xloge​(52​),x∈ S,y∈R}. Then, the sum of all the elements in the range of RRR is equal to :
  1. A
    32\frac{3}{2}23​
  2. B
    109\frac{10}{9}910​
  3. C
    52\frac{5}{2}25​
  4. D
    53\frac{5}{3}35​
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