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Sequences and Series question

2020 · 9 Jan · Shift 2 · Q40
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  5. /2020 · 9 Jan · Shift 2 · Q40

Sequences and Series question

2020 · 9 Jan · Shift 2 · Q40

JEE MainMathematicsSequences and SeriesMCQ+4 / −1
Let an be the nth term of a G.P. of positive terms. ∑n=1100a2n+1=200\sum\limits_{n = 1}^{100} {{a_{2n + 1}} = 200}n=1∑100​a2n+1​=200 and ∑n=1100a2n=100\sum\limits_{n = 1}^{100} {{a_{2n}} = 100}n=1∑100​a2n​=100, then ∑n=1200an\sum\limits_{n = 1}^{200} {{a_n}}n=1∑200​an​ is equal to :
  1. A
    150
  2. B
    175
  3. C
    225
  4. D
    300
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