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Permutations and Combinations question

2018 · 15 Apr · Shift 1 · Q26
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Permutations and Combinations question

2018 · 15 Apr · Shift 1 · Q26

JEE MainMathematicsPermutations and CombinationsMCQ+4 / −1
n −-− digit numbers are formed using only three digits 2, 5 and 7. The smallest value of n for which 900 such distinct numbers can be formed, is :
  1. A
    6
  2. B
    7
  3. C
    8
  4. D
    9
View written solutionFree

Correct answer: B

  1. Understand the formation rule

    We can form nnn-digit numbers using only the digits 2,5,72, 5, 72,5,7.

    For each of the nnn positions, there are exactly 333 choices: 2, 5, 72,\ 5,\ 72, 5, 7

    Hence, the total number of distinct nnn-digit numbers is 3n.3^n.3n.

  2. Apply the condition

    We need the smallest nnn such that at least 900900900 distinct numbers can be formed: 3n≥900.3^n \ge 900.3n≥900.

  3. Check powers of 3

    35=2433^5 = 24335=243 36=7293^6 = 72936=729 37=21873^7 = 218737=2187

    Now, 729<900<2187729 < 900 < 2187729<900<2187

    So the smallest value of nnn satisfying 3n≥9003^n \ge 9003n≥900 is n=7.n=7.n=7.

  4. Match with options

    Option BBB is 777.

  5. Compare with stored correct answer

    Stored correct answer: BBB

    Our derived answer is also BBB.

    Therefore, the stored answer is correct.

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