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Limits Continuity and Differentiability question

2025 · 29 Jan · Shift 1 · Q46
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  5. /2025 · 29 Jan · Shift 1 · Q46

Limits Continuity and Differentiability question

2025 · 29 Jan · Shift 1 · Q46

JEE MainMathematicsLimits Continuity and DifferentiabilityNumerical+4 / −1
Let [t] be the greatest integer less than or equal to t. Then the least value of p ∈ N for which lim⁡x→0+(x([1x]+[2x]+…+[px])−x2([1x2]+[22x2]+…+[92x2])≥1\lim\limits_{x \to 0^+} \left( x (\left[ \frac{1}{x} \right] + \left[ \frac{2}{x} \right] + \ldots + \left[ \frac{p}{x} \right] \right) - x^2 \left( \left[ \frac{1}{x^2} \right] + \left[ \frac{2^2}{x^2} \right] + \ldots + \left[ \frac{9^2}{x^2} \right] \right) \geq 1x→0+lim​(x([x1​]+[x2​]+…+[xp​])−x2([x21​]+[x222​]+…+[x292​])≥1 is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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