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Limits Continuity and Differentiability question

2025 · 28 Jan · Shift 2 · Q46
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Limits Continuity and Differentiability question

2025 · 28 Jan · Shift 2 · Q46

JEE MainMathematicsLimits Continuity and DifferentiabilityNumerical+4 / −1
Let f(x)=lim⁡n→∞∑r=0n(tan⁡(x/2r+1)+tan⁡3(x/2r+1)1−tan⁡2(x/2r+1))f(x)=\lim \limits_{n \rightarrow \infty} \sum\limits_{r=0}^n\left(\frac{\tan \left(x / 2^{r+1}\right)+\tan ^3\left(x / 2^{r+1}\right)}{1-\tan ^2\left(x / 2^{r+1}\right)}\right)f(x)=n→∞lim​r=0∑n​(1−tan2(x/2r+1)tan(x/2r+1)+tan3(x/2r+1)​) Then lim⁡x→0ex−ef(x)(x−f(x))\lim\limits_{x \rightarrow 0} \frac{e^x-e^{f(x)}}{(x-f(x))}x→0lim​(x−f(x))ex−ef(x)​ is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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