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Limits Continuity and Differentiability question

2021 · 27 Aug · Shift 1 · Q29

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JEE Main
Mathematics
Limits Continuity and Differentiability
2021 · 27 Aug · Shift 1 · Q29

Limits Continuity and Differentiability question

2021 · 27 Aug · Shift 1 · Q29

JEE MainMathematicsLimits Continuity and DifferentiabilityMCQ+4 / −1

If

\alpha

,

\beta

are the distinct roots of x2 + bx + c = 0, then

\mathop {\lim }\limits_{x \to \beta } {{{e^{2({x^2} + bx + c)}} - 1 - 2({x^2} + bx + c)} \over {{{(x - \beta )}^2}}}

is equal to :

A
b2 + 4c
B
2(b2 + 4c)
C
2(b2 $-$ 4c)
D
b2 $-$ 4c

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