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Limits Continuity and Differentiability question

2019 · 8 Apr · Shift 1 · Q34

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PYQ Library
JEE Main
Mathematics
Limits Continuity and Differentiability
2019 · 8 Apr · Shift 1 · Q34

Limits Continuity and Differentiability question

2019 · 8 Apr · Shift 1 · Q34

JEE MainMathematicsLimits Continuity and DifferentiabilityMCQ+4 / −1

\mathop {\lim }\limits_{x \to 0} {{{{\sin }^2}x} \over {\sqrt 2 - \sqrt {1 + \cos x} }}

equals:

A
$\sqrt 2$
B
$2 \sqrt 2$
C
4
D
$4 \sqrt 2$

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