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Inverse Trigonometric Functions question

2017 · 8 Apr · Shift 1 · Q35
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  5. /2017 · 8 Apr · Shift 1 · Q35

Inverse Trigonometric Functions question

2017 · 8 Apr · Shift 1 · Q35

JEE MainMathematicsInverse Trigonometric FunctionsMCQ+4 / −1
The value of tan-1 [1+x2+1−x21+x2−1−x2],∣x∣<12,xe0,\left[ {{{\sqrt {1 + {x^2}} + \sqrt {1 - {x^2}} } \over {\sqrt {1 + {x^2}} - \sqrt {1 - {x^2}} }}} \right],\left| x \right| \lt {1 \over 2},x e 0,[1+x2​−1−x2​1+x2​+1−x2​​],∣x∣<21​,xe0, is equal to :
  1. A
    π4+12cos⁡−1 x2{\pi \over 4} + {1 \over 2}{\cos ^{ - 1}}\,{x^2}4π​+21​cos−1x2
  2. B
    π4+cos⁡−1 x2{\pi \over 4} + {\cos ^{ - 1}}\,{x^2}4π​+cos−1x2
  3. C
    π4−12cos⁡−1 x2{\pi \over 4} - {1 \over 2}{\cos ^{ - 1}}\,{x^2}4π​−21​cos−1x2
  4. D
    π4−cos⁡−1 x2{\pi \over 4} - {\cos ^{ - 1}}\,{x^2}4π​−cos−1x2
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