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Inverse Trigonometric Functions question

2005 · Shift 0 · Q83
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  5. /2005 · Shift 0 · Q83

Inverse Trigonometric Functions question

2005 · Shift 0 · Q83

JEE MainMathematicsInverse Trigonometric FunctionsMCQ+4 / −1
If cos⁡−1x−cos⁡−1y2=α,{\cos ^{ - 1}}x - {\cos ^{ - 1}}{y \over 2} = \alpha ,cos−1x−cos−12y​=α, then 4x2−4xycos⁡α+y24{x^2} - 4xy\cos \alpha + {y^2}4x2−4xycosα+y2 is equal to :
  1. A
    2sin⁡2α2\sin 2\alpha2sin2α
  2. B
    444
  3. C
    4sin⁡2α4{\sin ^2}\alpha4sin2α
  4. D
    −4sin⁡2α-4{\sin ^2}\alpha−4sin2α
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