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Indefinite Integrals question

2025 · 4 Apr · Shift 2 · Q46
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Indefinite Integrals question

2025 · 4 Apr · Shift 2 · Q46

JEE MainMathematicsIndefinite IntegralsNumerical+4 / −1
If ∫(1+x2+x)10(1+x2−x)9 dx=1 m((1+x2+x)n(n1+x2−x))+C\int \frac{\left(\sqrt{1+x^2}+x\right)^{10}}{\left(\sqrt{1+x^2}-x\right)^9} \mathrm{~d} x=\frac{1}{\mathrm{~m}}\left(\left(\sqrt{1+x^2}+x\right)^{\mathrm{n}}\left(\mathrm{n} \sqrt{1+x^2}-x\right)\right)+\mathrm{C}∫(1+x2​−x)9(1+x2​+x)10​ dx= m1​((1+x2​+x)n(n1+x2​−x))+C where C is the constant of integration and m,n∈N\mathrm{m}, \mathrm{n} \in \mathbf{N}m,n∈N, then m+n\mathrm{m}+\mathrm{n}m+n is equal to ‾\underline{\hspace{2cm}}​ .
Numerical answer
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