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Indefinite Integrals question

2021 · 25 Feb · Shift 1 · Q34
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  5. /2021 · 25 Feb · Shift 1 · Q34

Indefinite Integrals question

2021 · 25 Feb · Shift 1 · Q34

JEE MainMathematicsIndefinite IntegralsMCQ+4 / −1
The value of the integral ∫sin⁡θ.sin⁡2θ(sin⁡6θ+sin⁡4θ+sin⁡2θ)2sin⁡4θ+3sin⁡2θ+61−cos⁡2θ dθ\int {{{\sin \theta .\sin 2\theta ({{\sin }^6}\theta + {{\sin }^4}\theta + {{\sin }^2}\theta )\sqrt {2{{\sin }^4}\theta + 3{{\sin }^2}\theta + 6} } \over {1 - \cos 2\theta }}} \,d\theta∫1−cos2θsinθ.sin2θ(sin6θ+sin4θ+sin2θ)2sin4θ+3sin2θ+6​​dθ is :
  1. A
    118[9−2cos⁡6θ−3cos⁡4θ−6cos⁡2θ]32+c{1 \over {18}}{\left[ {9 - 2{{\cos }^6}\theta - 3{{\cos }^4}\theta - 6{{\cos }^2}\theta } \right]^{{3 \over 2}}} + c181​[9−2cos6θ−3cos4θ−6cos2θ]23​+c
  2. B
    118[11−18sin⁡2θ+9sin⁡4θ−2sin⁡6θ]32+c{1 \over {18}}{\left[ {11 - 18{{\sin }^2}\theta + 9{{\sin }^4}\theta - 2{{\sin }^6}\theta } \right]^{{3 \over 2}}} + c181​[11−18sin2θ+9sin4θ−2sin6θ]23​+c
  3. C
    118[11−18cos⁡2θ+9cos⁡4θ−2cos⁡6θ]32+c{1 \over {18}}{\left[ {11 - 18{{\cos }^2}\theta + 9{{\cos }^4}\theta - 2{{\cos }^6}\theta } \right]^{{3 \over 2}}} + c181​[11−18cos2θ+9cos4θ−2cos6θ]23​+c
  4. D
    118[9−2sin⁡6θ−3sin⁡4θ−6sin⁡2θ]32+c{1 \over {18}}{\left[ {9 - 2{{\sin }^6}\theta - 3{{\sin }^4}\theta - 6{{\sin }^2}\theta } \right]^{{3 \over 2}}} + c181​[9−2sin6θ−3sin4θ−6sin2θ]23​+c
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