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Functions question

2021 · 17 Mar · Shift 1 · Q29
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  5. /2021 · 17 Mar · Shift 1 · Q29

Functions question

2021 · 17 Mar · Shift 1 · Q29

JEE MainMathematicsFunctionsMCQ+4 / −1
The inverse of y=5log⁡xy = {5^{\log x}}y=5logx is :
  1. A
    x=5log⁡yx = {5^{\log y}}x=5logy
  2. B
    x=y1log⁡5x = {y^{{1 \over {\log 5}}}}x=ylog51​
  3. C
    x=51log⁡yx = {5^{{1 \over {\log y}}}}x=5logy1​
  4. D
    x=ylog⁡5x = {y^{\log 5}}x=ylog5
View written solutionFree

Correct answer: B

  1. Given function

    y=5log⁡xy = 5^{\log x}y=5logx

    We need to find its inverse, i.e. express xxx in terms of yyy.

  2. Take logarithm on both sides

    Using logarithm on both sides,

    log⁡y=log⁡(5log⁡x)\log y = \log\left(5^{\log x}\right)logy=log(5logx)

    Now apply the power rule:

    log⁡y=(log⁡x)(log⁡5)\log y = (\log x)(\log 5)logy=(logx)(log5)

  3. Solve for log⁡x\log xlogx

    log⁡x=log⁡ylog⁡5\log x = \frac{\log y}{\log 5}logx=log5logy​

  4. Exponentiate to get xxx

    x=10log⁡ylog⁡5x = 10^{\frac{\log y}{\log 5}}x=10log5logy​

    Using the identity

    10log⁡a=a10^{\log a} = a10loga=a

    we rewrite:

    x=y1log⁡5x = y^{\frac{1}{\log 5}}x=ylog51​

  5. Match with the options

    This is exactly:

    x=y1log⁡5x = y^{\frac{1}{\log 5}}x=ylog51​

    So the correct option is B.

  6. Quick verification

    From

    y=5log⁡xy = 5^{\log x}y=5logx

    note that

    5log⁡x=10(log⁡5)(log⁡x)=xlog⁡55^{\log x} = 10^{(\log 5)(\log x)} = x^{\log 5}5logx=10(log5)(logx)=xlog5

    Hence

    y=xlog⁡5y = x^{\log 5}y=xlog5

    Therefore,

    x=y1/log⁡5x = y^{1/\log 5}x=y1/log5

    which confirms the result.

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