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Differentiation question

2020 · 9 Jan · Shift 2 · Q33
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Differentiation question

2020 · 9 Jan · Shift 2 · Q33

JEE MainMathematicsDifferentiationMCQ+4 / −1
If x=2sin⁡θ−sin⁡2θx = 2\sin \theta - \sin 2\thetax=2sinθ−sin2θ and y=2cos⁡θ−cos⁡2θy = 2\cos \theta - \cos 2\thetay=2cosθ−cos2θ, θ∈[0,2π]\theta \in \left[ {0,2\pi } \right]θ∈[0,2π], then d2ydx2{{{d^2}y} \over {d{x^2}}}dx2d2y​ at θ\thetaθ=π\piπ is :
  1. A
    38{3 \over 8}83​
  2. B
    32{3 \over 2}23​
  3. C
    34{3 \over 4}43​
  4. D
    -34{3 \over 4}43​
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