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Differential Equations question

2025 · 24 Jan · Shift 1 · Q34

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JEE Main
Mathematics
Differential Equations
2025 · 24 Jan · Shift 1 · Q34

Differential Equations question

2025 · 24 Jan · Shift 1 · Q34

JEE MainMathematicsDifferential EquationsMCQ+4 / −1

Let

\mathrm{y}=\mathrm{y}(\mathrm{x})

be the solution of the differential equation

\left(x y-5 x^2 \sqrt{1+x^2}\right) d x+\left(1+x^2\right) d y=0, y(0)=0

. Then

y(\sqrt{3})

is equal to

A
$\frac{5 \sqrt{3}}{2}$
B
$\sqrt{\frac{15}{2}}$
C
$\sqrt{\frac{14}{3}}$
D
$2 \sqrt{2}$

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