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Differential Equations question

2019 · 12 Jan · Shift 1 · Q45

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JEE Main
Mathematics
Differential Equations
2019 · 12 Jan · Shift 1 · Q45

Differential Equations question

2019 · 12 Jan · Shift 1 · Q45

JEE MainMathematicsDifferential EquationsMCQ+4 / −1

Let y = y(x) be the solution of the differential equation, x

{{dy} \over {dx}}

+ y = x loge x, (x > 1). If 2y(2) = loge 4

-

1, then y(e) is equal to :

A
$- {e \over 2}$
B
$- {{{e^2}} \over 2}$
C
${{{e^2}} \over 4}$
D
${e \over 4}$

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