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Differential Equations question

2018 · Shift 0 · Q38

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PYQ Library
JEE Main
Mathematics
Differential Equations
2018 · Shift 0 · Q38

Differential Equations question

2018 · Shift 0 · Q38

JEE MainMathematicsDifferential EquationsMCQ+4 / −1

Let y = y(x) be the solution of the differential equation

\sin x{{dy} \over {dx}} + y\cos x = 4x

,

x \in \left( {0,\pi } \right)

. If

y\left( {{\pi \over 2}} \right) = 0

, then

y\left( {{\pi \over 6}} \right)

is equal to :

A
$- {4 \over 9}{\pi ^2}$
B
${4 \over {9\sqrt 3 }}{\pi ^2}$
C
$- {8 \over {9\sqrt 3 }}{\pi ^2}$
D
$- {8 \over 9}{\pi ^2}$

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