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Differential Equations question

2015 · Shift 0 · Q28
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  1. PYQ Library
  2. /JEE Main
  3. /Mathematics
  4. /Differential Equations
  5. /2015 · Shift 0 · Q28

Differential Equations question

2015 · Shift 0 · Q28

JEE MainMathematicsDifferential EquationsMCQ+4 / −1
Let y(x)y(x)y(x) be the solution of the differential equation (x log⁡x)dydx+y=2x log⁡x,(x≥1).\left( {x\,\log x} \right){{dy} \over {dx}} + y = 2x\,\log x,\left( {x \ge 1} \right).(xlogx)dxdy​+y=2xlogx,(x≥1). Then y(e)y(e)y(e) is equal to :
  1. A
    222
  2. B
    2e2e2e
  3. C
    eee
  4. D
    000
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