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Definite Integration question

2025 · 29 Jan · Shift 1 · Q49
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  5. /2025 · 29 Jan · Shift 1 · Q49

Definite Integration question

2025 · 29 Jan · Shift 1 · Q49

JEE MainMathematicsDefinite IntegrationNumerical+4 / −1
Let f:(0,∞)→Rf:(0, \infty) \rightarrow \mathbf{R}f:(0,∞)→R be a twice differentiable function. If for some ae0,∫01f(λx)dλ=af(x),f(1)=1a e 0, \int\limits_0^1 f(\lambda x) \mathrm{d} \mathrm{\lambda}=a f(x), f(1)=1ae0,0∫1​f(λx)dλ=af(x),f(1)=1 and f(16)=18f(16)=\frac{1}{8}f(16)=81​, then 16−f′(116)16-f^{\prime}\left(\frac{1}{16}\right)16−f′(161​) is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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