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Definite Integration question

2022 · 24 Jun · Shift 1 · Q41
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  5. /2022 · 24 Jun · Shift 1 · Q41

Definite Integration question

2022 · 24 Jun · Shift 1 · Q41

JEE MainMathematicsDefinite IntegrationNumerical+4 / −1
Let Max0 ≤x ≤2{9−x25−x}=α\mathop {Max}\limits_{0\, \le x\, \le 2} \left\{ {{{9 - {x^2}} \over {5 - x}}} \right\} = \alpha0≤x≤2Max​{5−x9−x2​}=α and Min0 ≤x ≤2{9−x25−x}=β\mathop {Min}\limits_{0\, \le x\, \le 2} \left\{ {{{9 - {x^2}} \over {5 - x}}} \right\} = \beta0≤x≤2Min​{5−x9−x2​}=β. If ∫β−832α−1Max{9−x25−x,x}dx=α1+α2log⁡e(815)\int\limits_{\beta - {8 \over 3}}^{2\alpha - 1} {Max\left\{ {{{9 - {x^2}} \over {5 - x}},x} \right\}dx = {\alpha _1} + {\alpha _2}{{\log }_e}\left( {{8 \over {15}}} \right)}β−38​∫2α−1​Max{5−x9−x2​,x}dx=α1​+α2​loge​(158​) then α1+α2{\alpha _1} + {\alpha _2}α1​+α2​ is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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