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Definite Integration question

2021 · 24 Feb · Shift 2 · Q28
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  5. /2021 · 24 Feb · Shift 2 · Q28

Definite Integration question

2021 · 24 Feb · Shift 2 · Q28

JEE MainMathematicsDefinite IntegrationMCQ+4 / −1
Let f be a twice differentiable function defined on R such that f(0) = 1, f'(0) = 2 and f'(x) eee 0 for all x ∈\in∈ R. If ∣f(x)f′(x)f′(x)f′′(x)∣\left| {\begin{matrix} {f(x)} & {f'(x)} \\ {f'(x)} & {f''(x)} \\ \end{matrix} } \right|​f(x)f′(x)​f′(x)f′′(x)​​ = 0, for all x ∈\in∈ R, then the value of f(1) lies in the interval :
  1. A
    (0, 3)
  2. B
    (9, 12)
  3. C
    (3, 6)
  4. D
    (6, 9)
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