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Complex Numbers question

2022 · 26 Jun · Shift 2 · Q41
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  5. /2022 · 26 Jun · Shift 2 · Q41

Complex Numbers question

2022 · 26 Jun · Shift 2 · Q41

JEE MainMathematicsComplex NumbersNumerical+4 / −1
If z2+z+1=0{z^2} + z + 1 = 0z2+z+1=0, z∈Cz \in Cz∈C, then ∣∑n=115(zn+(−1)n1zn)2∣\left| {\sum\limits_{n = 1}^{15} {{{\left( {{z^n} + {{( - 1)}^n}{1 \over {{z^n}}}} \right)}^2}} } \right|​n=1∑15​(zn+(−1)nzn1​)2​ is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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