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Circle question

2016 · Shift 0 · Q32
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  5. /2016 · Shift 0 · Q32

Circle question

2016 · Shift 0 · Q32

JEE MainMathematicsCircleMCQ+4 / −1
If one of the diameters of the circle, given by the equation, x2+y2−4x+6y−12=0,{x^2} + {y^2} - 4x + 6y - 12 = 0,x2+y2−4x+6y−12=0, is a chord of a circle SSS, whose centre is at (−3,2)(-3, 2)(−3,2), then the radius of SSS is :
  1. A
    555
  2. B
    101010
  3. C
    525\sqrt 252​
  4. D
    535\sqrt 353​
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