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Binomial Theorem question

2019 · 10 Jan · Shift 1 · Q33
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  2. /JEE Main
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  5. /2019 · 10 Jan · Shift 1 · Q33

Binomial Theorem question

2019 · 10 Jan · Shift 1 · Q33

JEE MainMathematicsBinomial TheoremMCQ+4 / −1
If the third term in the binomial expansion of (1+xlog⁡2x)5{\left( {1 + {x^{{{\log }_2}x}}} \right)^5}(1+xlog2​x)5 equals 2560, then a possible value of x is -
  1. A
    222\sqrt 222​
  2. B
    424\sqrt 242​
  3. C
    18{1 \over 8}81​
  4. D
    14{1 \over 4}41​
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