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Binomial Theorem question

2019 · 12 Apr · Shift 2 · Q29
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  2. /JEE Main
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  5. /2019 · 12 Apr · Shift 2 · Q29

Binomial Theorem question

2019 · 12 Apr · Shift 2 · Q29

JEE MainMathematicsBinomial TheoremMCQ+4 / −1
The term independent of x in the expansion of (160−x881).(2x2−3x2)6\left( {{1 \over {60}} - {{{x^8}} \over {81}}} \right).{\left( {2{x^2} - {3 \over {{x^2}}}} \right)^6}(601​−81x8​).(2x2−x23​)6 is equal to :
  1. A
    36
  2. B
    - 108
  3. C
    - 36
  4. D
    - 72
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