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Area Under the Curves question

2023 · 29 Jan · Shift 1 · Q37
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  5. /2023 · 29 Jan · Shift 1 · Q37

Area Under the Curves question

2023 · 29 Jan · Shift 1 · Q37

JEE MainMathematicsArea Under the CurvesMCQ+4 / −1
Let A={(x,y)∈R2:y≥0,2x≤y≤4−(x−1)2}A=\left\{(x, y) \in \mathbb{R}^{2}: y \geq 0,2 x \leq y \leq \sqrt{4-(x-1)^{2}}\right\}A={(x,y)∈R2:y≥0,2x≤y≤4−(x−1)2​} and B={(x,y)∈R×R:0≤y≤min⁡{2x,4−(x−1)2}}. B=\left\{(x, y) \in \mathbb{R} \times \mathbb{R}: 0 \leq y \leq \min \left\{2 x, \sqrt{4-(x-1)^{2}}\right\}\right\} \text {. }B={(x,y)∈R×R:0≤y≤min{2x,4−(x−1)2​}}. . Then the ratio of the area of A to the area of B is
  1. A
    ππ+1\frac{\pi}{\pi+1}π+1π​
  2. B
    π−1π+1\frac{\pi-1}{\pi+1}π+1π−1​
  3. C
    ππ−1\frac{\pi}{\pi-1}π−1π​
  4. D
    π+1π−1\frac{\pi+1}{\pi-1}π−1π+1​
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