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Area Under the Curves question

2022 · 27 Jul · Shift 1 · Q32

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JEE Main
Mathematics
Area Under the Curves
2022 · 27 Jul · Shift 1 · Q32

Area Under the Curves question

2022 · 27 Jul · Shift 1 · Q32

JEE MainMathematicsArea Under the CurvesMCQ+4 / −1

The area of the smaller region enclosed by the curves

y^{2}=8 x+4

and

x^{2}+y^{2}+4 \sqrt{3} x-4=0

is equal to

A
$\frac{1}{3}(2-12 \sqrt{3}+8 \pi)$
B
$\frac{1}{3}(2-12 \sqrt{3}+6 \pi)$
C
$\frac{1}{3}(4-12 \sqrt{3}+8 \pi)$
D
$\frac{1}{3}(4-12 \sqrt{3}+6 \pi)$

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