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Area Under the Curves question

2022 · 25 Jul · Shift 2 · Q44

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JEE Main
Mathematics
Area Under the Curves
2022 · 25 Jul · Shift 2 · Q44

Area Under the Curves question

2022 · 25 Jul · Shift 2 · Q44

JEE MainMathematicsArea Under the CurvesNumerical+4 / −1

Let the area enclosed by the x-axis, and the tangent and normal drawn to the curve

4{x^3} - 3x{y^2} + 6{x^2} - 5xy - 8{y^2} + 9x + 14 = 0

at the point (

-

2, 3) be A. Then 8A is equal to

\underline{\hspace{2cm}}

.

Numerical answer

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