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Area Under the Curves question

2018 · Shift 0 · Q41

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PYQ Library
JEE Main
Mathematics
Area Under the Curves
2018 · Shift 0 · Q41

Area Under the Curves question

2018 · Shift 0 · Q41

JEE MainMathematicsArea Under the CurvesMCQ+4 / −1

Let g(x) = cosx2, f(x) =

\sqrt x

and

\alpha ,\beta \left( {\alpha \lt \beta } \right)

be the roots of the quadratic equation 18x2 - 9

\pi

x +

{\pi ^2}

= 0. Then the area (in sq. units) bounded by the curve y = (gof)(x) and the lines

x = \alpha

,

x = \beta

and y = 0 is :

A
${1 \over 2}\left( {\sqrt 2 - 1} \right)$
B
${1 \over 2}\left( {\sqrt 3 - 1} \right)$
C
${1 \over 2}\left( {\sqrt 3 + 1} \right)$
D
${1 \over 2}\left( {\sqrt 3 - \sqrt 2 } \right)$

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