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3D Geometry question

2023 · 1 Feb · Shift 1 · Q25

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JEE Main
Mathematics
3D Geometry
2023 · 1 Feb · Shift 1 · Q25

3D Geometry question

2023 · 1 Feb · Shift 1 · Q25

JEE MainMathematics3D GeometryMCQ+4 / −1

The shortest distance between the lines

{{x - 5} \over 1} = {{y - 2} \over 2} = {{z - 4} \over { - 3}}

and

{{x + 3} \over 1} = {{y + 5} \over 4} = {{z - 1} \over { - 5}}

is :

A
$7\sqrt 3$
B
$5\sqrt 3$
C
$4\sqrt 3$
D
$6\sqrt 3$

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