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3D Geometry question

2024 · 5 Apr · Shift 2 · Q54

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JEE Main
Mathematics
3D Geometry
2024 · 5 Apr · Shift 2 · Q54

3D Geometry question

2024 · 5 Apr · Shift 2 · Q54

JEE MainMathematics3D GeometryNumerical+4 / −1

Let the point

(-1, \alpha, \beta)

lie on the line of the shortest distance between the lines

\frac{x+2}{-3}=\frac{y-2}{4}=\frac{z-5}{2}

and

\frac{x+2}{-1}=\frac{y+6}{2}=\frac{z-1}{0}

. Then

(\alpha-\beta)^2

is equal to

\underline{\hspace{2cm}}

.

Numerical answer

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