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3D Geometry question

2022 · 26 Jun · Shift 1 · Q30
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  2. /JEE Main
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  5. /2022 · 26 Jun · Shift 1 · Q30

3D Geometry question

2022 · 26 Jun · Shift 1 · Q30

JEE MainMathematics3D GeometryMCQ+4 / −1
If the two lines l1:x−23=y+1−2, z=2{l_1}:{{x - 2} \over 3} = {{y + 1} \over {-2}},\,z = 2l1​:3x−2​=−2y+1​,z=2 and l2:x−11=2y+3α=z+52{l_2}:{{x - 1} \over 1} = {{2y + 3} \over \alpha } = {{z + 5} \over 2}l2​:1x−1​=α2y+3​=2z+5​ are perpendicular, then an angle between the lines l2 and l3:1−x3=2y−1−4=z4{l_3}:{{1 - x} \over 3} = {{2y - 1} \over { - 4}} = {z \over 4}l3​:31−x​=−42y−1​=4z​ is :
  1. A
    cos⁡−1(294){\cos ^{ - 1}}\left( {{{29} \over 4}} \right)cos−1(429​)
  2. B
    sec⁡−1(294){\sec ^{ - 1}}\left( {{{29} \over 4}} \right)sec−1(429​)
  3. C
    cos⁡−1(229){\cos ^{ - 1}}\left( {{2 \over {29}}} \right)cos−1(292​)
  4. D
    cos⁡−1(229){\cos ^{ - 1}}\left( {{2 \over {\sqrt {29} }}} \right)cos−1(29​2​)
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