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Thermodynamics question

2023 · 31 Jan · Shift 1 · Q18
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Thermodynamics question

2023 · 31 Jan · Shift 1 · Q18

JEE MainChemistryThermodynamicsNumerical+4 / −1
The enthalpy change for the conversion of 12Cl2( g)\frac{1}{2} \mathrm{Cl}_{2}(\mathrm{~g})21​Cl2​( g) to Cl−\mathrm{Cl}^{-}Cl−(aq) is (−-−) ‾kJmol−1\underline{\hspace{2cm}}\mathrm{kJ} \mathrm{mol}^{-1}​kJmol−1(Nearest integer) Given : ΔdisHCl2( g)θ⊖=240 kJ mol−1,ΔegHCl(g)⊖=−350 kJ mol−1\Delta_{\mathrm{dis}} \mathrm{H}_{\mathrm{Cl}_{2(\mathrm{~g})}^{\theta}}^{\ominus}=240 \mathrm{~kJ} \mathrm{~mol}^{-1}, \Delta_{\mathrm{eg}} \mathrm{H}_{\mathrm{Cl_{(g)}}}^{\ominus}=-350 \mathrm{~kJ} \mathrm{~mol}^{-1}Δdis​HCl2( g)θ​⊖​=240 kJ mol−1,Δeg​HCl(g)​⊖​=−350 kJ mol−1, ΔhydHCl(g)−Θ=−380{\mathrm{\Delta _{hyd}}H_{Cl_{(g)}^ - }^\Theta = - 380}Δhyd​HCl(g)−​Θ​=−380 kJ mol−1\mathrm{kJ~mol^{-1}}kJ mol−1
Numerical answer
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