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Thermodynamics question

2022 · 25 Jul · Shift 2 · Q16
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  5. /2022 · 25 Jul · Shift 2 · Q16

Thermodynamics question

2022 · 25 Jul · Shift 2 · Q16

JEE MainChemistryThermodynamicsNumerical+4 / −1
While performing a thermodynamics experiment, a student made the following observations. HClHClHCl + NaOHNaOHNaOH →\to→ NaClNaClNaCl + H2OH_2OH2​O Δ\DeltaΔ H = −-− 57.3 kJ mol −-− 1 CH3COOHCH_3COOHCH3​COOH + NaOHNaOHNaOH →\to→ CH3COONaCH_3COONaCH3​COONa + H2OH_2OH2​O Δ\DeltaΔ H = −-− 55.3 kJ mol −-− 1 The enthalpy of ionization of CH3COOHCH_3COOHCH3​COOH as calculated by the student is ‾\underline{\hspace{2cm}}​ kJ mol −-− 1. (nearest integer)
Numerical answer
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