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Thermodynamics question

2023 · 13 Apr · Shift 1 · Q21
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  5. /2023 · 13 Apr · Shift 1 · Q21

Thermodynamics question

2023 · 13 Apr · Shift 1 · Q21

JEE MainChemistryThermodynamicsNumerical+4 / −1
A2+B2→2AB.ΔHf0=−200 kJ mol−1\mathrm{A}_{2}+\mathrm{B}_{2} \rightarrow 2 \mathrm{AB} . \Delta H_{f}^{0}=-200 \mathrm{~kJ} \mathrm{~mol}^{-1}A2​+B2​→2AB.ΔHf0​=−200 kJ mol−1 AB,A2\mathrm{AB}, \mathrm{A}_{2}AB,A2​ and B2\mathrm{B}_{2}B2​ are diatomic molecules. If the bond enthalpies of A2, B2\mathrm{A}_{2}, \mathrm{~B}_{2}A2​, B2​ and AB\mathrm{AB}AB are in the ratio 1:0.5:11: 0.5: 11:0.5:1, then the bond enthalpy of A2\mathrm{A}_{2}A2​ is ‾\underline{\hspace{2cm}}​kJ mol−1\mathrm{kJ} ~\mathrm{mol}^{-1}kJ mol−1 (Nearest integer)
Numerical answer
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