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Some Basic Concepts of Chemistry question

2020 · 3 Sep · Shift 2 · Q20

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Some Basic Concepts of Chemistry
2020 · 3 Sep · Shift 2 · Q20

Some Basic Concepts of Chemistry question

2020 · 3 Sep · Shift 2 · Q20

JEE MainChemistrySome Basic Concepts of ChemistryNumerical+4 / −1

The volume (in mL) of 0.1 N NaOH required to neutralise 10 mL of 0.1 N phosphinic acid is

\underline{\hspace{2cm}}

.

Numerical answer

View written solutionFree

Correct answer: 10

Use the normality relation for neutralisation

For acid-base neutralisation, $N_1 V_1 = N_2 V_2$ where:

$N_1, V_1$ are normality and volume of acid
$N_2, V_2$ are normality and volume of base

Given data

For phosphinic acid: $N_1 = 0.1\,N, \quad V_1 = 10\,\text{mL}$

For NaOH: $N_2 = 0.1\,N$

Let required volume of NaOH be $V_2$ .

Apply the formula

$0.1 \times 10 = 0.1 \times V_2$

$V_2 = 10\,\text{mL}$

Final answer

The required volume of $0.1\,N$ NaOH is $\boxed{10\,\text{mL}}$

Comparison with stored answer

Stored correct answer = $10$

My derived answer is also $10$ , so they match.

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