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Some Basic Concepts of Chemistry question

2017 · 9 Apr · Shift 1 · Q20
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Some Basic Concepts of Chemistry question

2017 · 9 Apr · Shift 1 · Q20

JEE MainChemistrySome Basic Concepts of ChemistryMCQ+4 / −1
What quantity (in mL) of a 45% acid solution of a mono-protic strong acid must be mixed with a 20% solution of the same acid to produce 800 mL of a 29.875% acid solution ?
  1. A
    320
  2. B
    325
  3. C
    316
  4. D
    330
View written solutionFree

Correct answer: C

  1. Let the volume of the 45%45\%45% acid solution be xxx mL.

  2. Then the volume of the 20%20\%20% acid solution must be: 800−x mL800 - x \text{ mL}800−x mL

  3. Since both are solutions of the same acid, we can equate the amount of acid before and after mixing.

Amount of acid from 45%45\%45% solution: 0.45x0.45x0.45x

Amount of acid from 20%20\%20% solution: 0.20(800−x)0.20(800-x)0.20(800−x)

Final amount of acid in 800800800 mL of 29.875%29.875\%29.875% solution: 0.29875×8000.29875 \times 8000.29875×800

  1. Form the equation: 0.45x+0.20(800−x)=0.29875×8000.45x + 0.20(800-x) = 0.29875 \times 8000.45x+0.20(800−x)=0.29875×800

  2. Simplify: 0.45x+160−0.20x=2390.45x + 160 - 0.20x = 2390.45x+160−0.20x=239 0.25x+160=2390.25x + 160 = 2390.25x+160=239 0.25x=790.25x = 790.25x=79 x=790.25=316x = \frac{79}{0.25} = 316x=0.2579​=316

  3. Therefore, the required volume of the 45%45\%45% acid solution is: 316 mL\boxed{316\text{ mL}}316 mL​

  4. Option check:

  • A: 320320320 ❌
  • B: 325325325 ❌
  • C: 316316316 ✅
  • D: 330330330 ❌

Hence, the correct option is C.

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