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Solutions question

2023 · 8 Apr · Shift 2 · Q17

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JEE Main
Chemistry
Solutions
2023 · 8 Apr · Shift 2 · Q17

Solutions question

2023 · 8 Apr · Shift 2 · Q17

JEE MainChemistrySolutionsNumerical+4 / −1

If the boiling points of two solvents X and Y (having same molecular weights) are in the ratio

2: 1

and their enthalpy of vaporizations are in the ratio

1: 2

, then the boiling point elevation constant of

\mathrm{X}

is

\underline{\mathrm{m}}

times the boiling point elevation constant of Y. The value of m is

\underline{\hspace{2cm}}

(nearest integer)

Numerical answer

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