JEE MainChemistrySolutionsNumerical+4 / −1
40 g of glucose (Molar mass = 180) is mixed with 200 mL of water. The freezing point of solution is K. (Nearest integer) [Given : Kf = 1.86 K kg mol 1; Density of water = 1.00 g cm 3; Freezing point of water = 273.15 K]
Numerical answer
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